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Python program to check if the given number is a Disarium Number
Python program to check if the given number is a Disarium Number
In this example, we will see a Python program through which we can check if the given number is a Disarium number or not.
Any given number will be a Disarium number if the sum of its digit raised to the power of their respective position is equal to the number itself.
Let’s take 175 as an example.
Now, 11+ 72 + 53 = 1+ 49 + 125 = 175
ALGORITHM:
- STEP 1:calculateLength() counts the digits present in a number.
- Use a while loop to check whether the number is not equal to 0.
- Divide the number by 10 and increment the variable-length by 1.
- Return length.
- STEP 2:Define and initialize variable num.
- STEP 3:Make a copy of num by storing the value of num in n.
- STEP 4:Using while loop calculates remainder rem repeatedly by dividing num with 10.
- STEP 5:Calculate the value of rem raised to power its position.
- STEP 6:Check whether the sum is equal to the number. If yes, then the given number is Disarium number. Else, it is not a Disarium number
#calculateLength() will count the digits present in a number
def calculateLength(n):
length = 0;
while(n != 0):
length = length + 1;
n = n//10;
return length;
num = 175;
rem = sum = 0;
len = calculateLength(num);
#Makes a copy of the original number num
n = num;
#Calculates the sum of digits powered with their respective position
while(num > 0):
rem = num%10;
sum = sum + int(rem**len);
num = num//10;
len = len - 1;
#Checks whether the sum is equal to the number itself
if(sum == n):
print(str(n) + " is a disarium number");
else:
print(str(n) + " is not a disarium number");
Output:
175 is a disarium number
175 is a disarium number
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